Question

If
b^2*c^2+b^2+c^2=243
a^2*c^2+a^2+c^2=1024
b^2*a^2+b^2+a^2=293
then what is (a+b+c)....?

Answer 1

i want any idea to start....

Answer 2

substitution... lots of times... until you have = a ...?, b = ...? and c = ...?

Answer 3

it kills lot of time...

Answer 4

b^2*c^2+b^2+c^2=243
therefore c^2 = 243 - b^2*c^2 - b^2
so c = sqrt (243 - b^2*c^2 - b^2)
theres your start, sub into eqn 2
rearrange eqn 2 for a = ... something...
sub THAT into eqn 3
rearrange so u end up with b = ...?

Answer 5

hey i have a better option

Answer 6

it is an interview question....

if we do like this...
it takes 1 hour to calculate...

Answer 7

ya tell me...@Aditya9826042721

Answer 8

we do it step by step

Answer 9

kk tell me your idea....

Answer 10

first let a^2=x
b^2 =y
c^2=z

Answer 11

sorry i have to go bcoz electricity gone i am on inverter

Answer 12

if u there then rply to continue

Answer 13

would u get the answer

Answer 14

im here ... shoot

Answer 15

from first equation
b^2c^2+b^2+c^2=243

Answer 16

take b^2 out and add 1both the side

Answer 17

as we get
b^2(c^2+1)+c^2+1=243 +1

Answer 18

now take out
(b^2+1)(c^2+1)=244

Answer 19

now similarly for all other equation
(a^2+1)(c^2+1)=1025

Answer 20

would u get it or not

Answer 21

are any one there....? :p

Answer 22

yeah dude, i follow so far

Answer 23

youre breakin them down to quadratics, then factoring

Answer 24

now we get three equation as about in multiplication form

Answer 25

now multiply all three equation to get
((b^2+1)^2)((a^2+1)^2)((c^2+1)^2)=244*1025*294

Answer 26

ya i am hear...
Net problem sorry...

Answer 27

now from either of equation
like
(b^2+1)(c^2+1)=244
put in last equation as
((244)^2)((a^2+1)^2)=244*1025*294
here u get equation of a
solve and get a
similarly for other

Answer 28

hope u get it

Answer 29

nice

Answer 30

thanks...........: )

Answer 31

been watching this. very clever!

Answer 32

thanks a lot ..........