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what is the polar form for x^2-2y^2 = 4 ?
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@mary.rojas Can help on this.
ahh.. okay. :) i'll tag her name. thank you. :)
@mary.rojas can you help me po?
Really,never even heard of polar form @AravindG
I guess you need to bring in sines and cosines.
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\[put~x=r~\cos \theta,y=r~\sin \theta \]
not it is an of hyperbola
here paramatric cordinate are \[\tan \theta and \]
\[r^2\cos ^2\theta-2r^2\sin ^2\theta=4,r^2\left( \cos ^2\theta-2\sin ^2\theta \right)=4\] r=?
not that use sec theta and tan theta
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