4. What is the probability that a randomly selected integer number between 1 and 1000 will not have a digit 7?
subtract \[1000-7=your answer\] You know that 7 is put between the numbers only once... so subtract 1000 and to get your probability!!!
There are 1000 numbers from 1 to 1000. How many of them have the digit 7?
oops I read the question wrong my bad...
? (For instance, 23 does not have a digit 7, but 73 and 277 both do.)
You need to count the numbers form 1 to 1000 that have the digit 7.
why don't you say 10,20,30 and count how many numbers between each of them have a 7. it'll be faster that way
1-P(one 7)-P(tewo 7's)-P(3 7's)
Here's a way of starting the count. Separate the numbers from 1 to 1000 into groups of 100. For example, start with integers from 1 to 100.
btw, i assume that between means not inclusive of the end points 1 & 1000.
1-10 how many 7's? 10-20 how many 7's? now keep doing that in sections of 10
isn't there any formula to do so? manual is the only way to count the number of 7's between 1- 1000?
no, that's the hard and confusing way. first, how many numbers total?
make your own formula if you can...
From 1 to 100: 7 17 27 37 47 57 67 All 70's, there are 10 of them 87 97 That is a total of 19.
@pgpilot326 it's not confusing if you write the numbers on a sheet of paper...|dw:1394391423161:dw|
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