Find an equation of the tangent line to the hyperbola: x^(2)-2y^(2)=1 at the point (a,b).
find m= dy/dx at point (a,b) then use equation (y-b)=m(x-a)
I found the slope= a/2b is that right?
yes right
What would the equation be then?
equation of a straight line is y=mx+c you know m put it in above eqn after that by putting point (a,b) you will get c so put c back in above equation you will get your final answer
Find an equation for the slope of the tangent line to the hyperbola: x^(2)-2y^(2)=1 by differentiating both sides with respect to x, and then solving the resulting equation for (dy/dx). That will be the formula for the slope of your tangent line. Remember that y is assumed to be a function of x here, so you'll need to use the chain rule in finding that derivative.
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