Question

Alright, I know it's Sunday but...a little help on an assignment we were supposed to fill out on our experiment? We're supposed to for each of our three trials state the following:
• heat needed to melt the ice (q)
• enthalpy of fusion
• percent error from the accepted enthalpy of fusion of water of 334 J/g
But I'm not quite sure how to do it. Could someone please explain? It'd be much appreciated! Thanks!

Answer 1

Oh and here is my data. That might be helpful. :)

Trial 1
Mass of calorimeter: 409g
Temp of calorimeter: 20Cº
Mass of calorimeter + water: 457g
Temp of calorimeter + water: 20Cº
Mass of calorimeter + water + ice: 510g
Temp of calorimeter + water + ice: –
Mass of calorimeter + ice: 450g
Temp of calorimeter + ice: 0Cº

Trial 2
Mass of calorimeter: 409g
Temp of calorimeter: 20Cº
Mass of calorimeter + water: 461g
Temp of calorimeter + water: 22Cº
Mass of calorimeter + water + ice: 515g
Temp of calorimeter + water + ice: –
Mass of calorimeter + ice: 447g
Temp of calorimeter + ice: 0Cº

Trial 3
Mass of calorimeter: 409g
Temp of calorimeter: 20Cº
Mass of calorimeter + water: 459g
Temp of calorimeter + water: 22Cº
Mass of calorimeter + water + ice: 513g
Temp of calorimeter + water + ice: –
Mass of calorimeter + ice: 448g
Temp of calorimeter + ice: 0Cº

Answer 2

Heat absorbed by the water = mass of the water * specific heat of water * change in temp

Answer 3

Sorry, I meant heat released from the water. In a calorimeter, you are assuming that all of the heat from the water goes to melting the ice.

Answer 4

Can you find the mass of the water?

Answer 5

In your first trial