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Mathematics 16 Online
OpenStudy (anonymous):

Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall. Approximately what percent of the adult male population is taller than the average basketball player? 0.13% 0.87% 49.87% 99.87%

OpenStudy (anonymous):

@srossd can you help?

OpenStudy (anonymous):

So, the average basketball player is 3 standard deviations above the mean. You can view here: http://4.bp.blogspot.com/_5u1UHojRiJk/TEh9BHxxPUI/AAAAAAAAAIQ/DafeQNMYFoE/s1600/ztable.gif That 99.87% of samples from a normal distribution are below that level (go down to Z=3.00 to see that). So, the answer is the complement, 0.13%.

OpenStudy (anonymous):

thanks so much! I have 2 other problems just like this and then I'm all done, are you up for it?

OpenStudy (anonymous):

Yeah, sure

OpenStudy (anonymous):

1) A car is designed to last an average of 12 years with a standard deviation of 0.8 years. What is the probability that a car will last less than 10 years? 0.621% 6.21% 93.79% 99.379% 2) The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 4. Approximately what percent of the trees are between 20 and 30 years old? 10.56% 68.32% 78.88% 89.44%

OpenStudy (anonymous):

I think the first one is A, is that right?

OpenStudy (anonymous):

1) So, you're 2/0.8 = 2.5 standard deviations below the mean. Using the same table as before, it's 0.62%. 2) We want to be within 1.2 standard deviations of the mean. Using the table, we see that 11.5% are above that level, and 11.5% are below that level, so that leaves 76.98%. I'm guessing they just used a slightly different table, so the answer is still C.

OpenStudy (anonymous):

ooh, okay thank you :)

OpenStudy (anonymous):

The first was correct! XD

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