An observer (O) spots a plane flying at a 35° angle to his horizontal line of sight. If the plane is flying at an altitude of 17,000 ft., what is the distance (x) from the plane (P) to the observer (O)?
20,757 feet 24,251 feet 29,639 feet 31,262 feet
I'm assuming you are working in a little trigonometry section? I can help if so
yes I am
ok great one sec, let me draw out a little diagram
okay thank you!!
|dw:1394405972374:dw|
To add on to my diagram, we are actually trying to find the hypotenuse of this triangle so we can use the angle we are given, and the altitude we are given to set up the sine of 35 degrees. sin35 = opposite(altitude)/hypotenuse(x) sin35 = 17,000/hypotenuse 17,000 time (sin35) = hypotenuse(x) So now we use our calculator to fin sin35 and multiply it by 17,000 and then you have x!
Would you like me to solve for X completely with my scientific calculator or are you good from here? @mathhelpxx
\(\bf sin(\textit{observer's angle})=\cfrac{\textit{altitude}}{x}\implies \textit{altitude}\cdot sin(\textit{observer's angle})=x\)
I got 9750 but i think its wrong @ChanHamm
ahemmm wait a sec... shoot \(\bf sin(\textit{observer's angle})=\cfrac{\textit{altitude}}{x}\implies x=\cfrac{\textit{altitude}}{sin(\textit{observer's angle})}\)
Let me check one second
That is correct!
But thats not an option
hmmm the hypotenuse will be longer than either side if one side is 17,000, the hypotenuse is surely more than that
Ok lets take a look at that I think we actually need to divide 17,000 by the sin35
\(\bf sin(\textit{observer's angle})=\cfrac{\textit{altitude}}{x}\implies x=\cfrac{\textit{altitude}}{sin(\textit{observer's angle})}\) notice ChanHamm 's picture
@jdoe0001 was correct I sort of messed up explaning x = altitude/ sin35
so would it be .00003374?
try this, 17,000 divided by the sin35
I got your third answer choice doing that
29638?
Yes! Good Job
oh I had to round it i see!
can you help me with another?
Yes, it would be much easier if you opened it in a new question. DO you mind
sure!
:)
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