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Mathematics 8 Online
OpenStudy (anonymous):

An observer (O) spots a plane flying at a 35° angle to his horizontal line of sight. If the plane is flying at an altitude of 17,000 ft., what is the distance (x) from the plane (P) to the observer (O)?

OpenStudy (anonymous):

20,757 feet 24,251 feet 29,639 feet 31,262 feet

OpenStudy (anonymous):

I'm assuming you are working in a little trigonometry section? I can help if so

OpenStudy (anonymous):

yes I am

OpenStudy (anonymous):

ok great one sec, let me draw out a little diagram

OpenStudy (anonymous):

okay thank you!!

OpenStudy (anonymous):

|dw:1394405972374:dw|

OpenStudy (anonymous):

To add on to my diagram, we are actually trying to find the hypotenuse of this triangle so we can use the angle we are given, and the altitude we are given to set up the sine of 35 degrees. sin35 = opposite(altitude)/hypotenuse(x) sin35 = 17,000/hypotenuse 17,000 time (sin35) = hypotenuse(x) So now we use our calculator to fin sin35 and multiply it by 17,000 and then you have x!

OpenStudy (anonymous):

Would you like me to solve for X completely with my scientific calculator or are you good from here? @mathhelpxx

OpenStudy (jdoe0001):

\(\bf sin(\textit{observer's angle})=\cfrac{\textit{altitude}}{x}\implies \textit{altitude}\cdot sin(\textit{observer's angle})=x\)

OpenStudy (anonymous):

I got 9750 but i think its wrong @ChanHamm

OpenStudy (jdoe0001):

ahemmm wait a sec... shoot \(\bf sin(\textit{observer's angle})=\cfrac{\textit{altitude}}{x}\implies x=\cfrac{\textit{altitude}}{sin(\textit{observer's angle})}\)

OpenStudy (anonymous):

Let me check one second

OpenStudy (anonymous):

That is correct!

OpenStudy (anonymous):

But thats not an option

OpenStudy (jdoe0001):

hmmm the hypotenuse will be longer than either side if one side is 17,000, the hypotenuse is surely more than that

OpenStudy (anonymous):

Ok lets take a look at that I think we actually need to divide 17,000 by the sin35

OpenStudy (jdoe0001):

\(\bf sin(\textit{observer's angle})=\cfrac{\textit{altitude}}{x}\implies x=\cfrac{\textit{altitude}}{sin(\textit{observer's angle})}\) notice ChanHamm 's picture

OpenStudy (anonymous):

@jdoe0001 was correct I sort of messed up explaning x = altitude/ sin35

OpenStudy (anonymous):

so would it be .00003374?

OpenStudy (anonymous):

try this, 17,000 divided by the sin35

OpenStudy (anonymous):

I got your third answer choice doing that

OpenStudy (anonymous):

29638?

OpenStudy (anonymous):

Yes! Good Job

OpenStudy (anonymous):

oh I had to round it i see!

OpenStudy (anonymous):

can you help me with another?

OpenStudy (anonymous):

Yes, it would be much easier if you opened it in a new question. DO you mind

OpenStudy (anonymous):

sure!

OpenStudy (anonymous):

:)

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