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f(x)=x4+2x3−3x2−4x+12
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What are the possible rational zeros of
The factors of the constant term divided by the factors of the coefficient of the leading term. The leading term is x^4 and its coefficient is 1. So the possible rational roots are the factors of 12.
none
there are no rational roots.
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± 1, ± 2, ± 3, ± 4, ± 6, ± 12 ± 1, ± 2, ± 3, ± 4, ± 5, ± 6, ± 7, ± 8, ± 9, ± 10, ± 11, ± 12 1, 2, 3, 4, 6, 12 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 these are the choices
@ hisham1 The problem asks for the possible rational roots. Not whether or not there are any.
Is 7 a factor of 12?
f(x)=x^4+2x^3−3x^2−4x+12
What are the factors of 12?
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