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OpenStudy (anonymous):

How to balance N2O5 +H2O --->HNO3

OpenStudy (anonymous):

count the atoms on each side. LEFT SIDE: 2 N atoms 6 O atoms 2 H atoms RIGHT SIDE: 1 N atom 3 O atoms 1 H atom we want both sides the same. notice that the right side has exactly twice the amount of each atom as the left side. so the only adjustment to be made for this one is to multiply the right side by 2: \[N_2 O_5 + H_2O ---> 2HNO_3\]

OpenStudy (anonymous):

Thank you very much

OpenStudy (anonymous):

glad to help C:

OpenStudy (anonymous):

Given the reaction is N2O5 + H2O ---> HNO3 on the left side of the reaction there are 2 nitrogen atoms, 6 oxygen atoms, 2 hydrogen atoms... but on the right side there are one hydrogen, one nitrogen atom, three oxygen atoms.... on the left side of the reaction there are double the number of atoms to that on the right side of the reaction.. thus, we can multiply by 2 so that there will be same number of atoms as that on left side thus, N2O5 + H2O ----> 2HNO3...

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