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Mathematics 9 Online
OpenStudy (anonymous):

P(-d

OpenStudy (anonymous):

Is \(z\) the standard normal distribution?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Divide 0.5408 by 2, Then use the resulting value of probability to find the value of z from the standardised normal distribution table. z = d.

OpenStudy (anonymous):

Okay, well from \(Z\)'s symmetry, you know that \(P(0<z<d)=\dfrac{1}{2}(0.5704)=0.2852\). Then \(P(0<Z<d)=P(Z<d)-P(Z<0)=\color{red}{P(Z<d)}-0.5=0.2852\). Solve for the red probability, then using a table find \(d\).

OpenStudy (anonymous):

thanks

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