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write the expression as a single natural logarithm 2 in x-4in c
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do you mean \[2\ln x-4\ln c\]?
\[n\log(x)=\log(x^n)\] \[\log(y)+\log(z)=\log(yz)\]
get those coefficient into the indices, then use the product property
the first one
ok so the answer would be... in (x^2-c^4)
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*Whops its a difference of logs, use the division property \[\log(x)-\log(y)=\log(x/y)\]
answer---> in x^2/c^4 or in C^4/x^2
idk which one lol
\[2\ln x-4\ln c=\ln x^2-\ln c^4=\ln (\cdots/\cdots)\]
in(x^2/C^4)
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right, in fact the division property is a special case of the product property \[\log(x)-\log(y)=\log(x)+\log(y^{-1})=\log(x)+\log(1/y)=\log(x/y)\]
thank you it makes more sense
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