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Mathematics 24 Online
OpenStudy (anonymous):

|2x-3|=11

OpenStudy (tkhunny):

What TWO values have the absolute value of 11?

OpenStudy (anonymous):

|2x – 3| = 11 2x – 3 = 11 or 2x – 3 = -11 2x = 11+3 or 2x = -11+3 2x = 14 or 2x = -8 x = 14/2 or x = -8/2 x = 7 or x = -4 So the solutions are x = 7 or x = -4

OpenStudy (anonymous):

can you help me with this one . . . . 5|2x+1|-3<7

OpenStudy (tkhunny):

Why is it different? Add 3 Divide by 5 What two values can you think of that have the resulting absolute value?

OpenStudy (anonymous):

I got the first one . its x< 1\2 I need help finding out the other one

OpenStudy (whpalmer4):

\[5|2x+1|-3<7\]Add 3 to each side \[5|2x+1| < 10\]Divide both sides by 5 \[|2x+1| < 2\] Now you have two cases: \[2x+1 < 2\]\[2x < 1\]\[x < \frac{1}{2}\] \[-(2x+1) < 2\] Solve in the same way, starting by distributing the -1 on the left side. Don't forget, if you multiply or divide by a negative number, you change the direction of the inequality sign.

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