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how many steps up from \(f\) to \(g\) ?
yeah, satellite73 just summed up everything i was trying to say in my post lol
I don't know
think of it like stairs
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Is it 2?
you have f(x) which starts at 0, yes? and then goes up-right extending
yep, cause g(x) starts out 2 more than f(x) and you can imply they extend at the same rate even tho thats not given
Thanks :)
well actually i guess it is given by g(x) = f(x) + k, cause no matter what f(x) is g(x) will always be k more than it. (in this instance, 2 more than it)
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I wish I could give you a medal too @satellite73 :( sorry
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