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find the fist derivative to f(x)=1+2e^-x+xe^-x
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\[f(x)=1+2e ^{-x}-xe ^{-x}\]
is it the first one or the second one?
the first
\[f(x) = 1 + 2e^{-x} - xe^{-x}\] \[f'(x) = -2e^{-x} -e^{-x} + x e^{-x}\]
Ok! The answer is: \[f'(x)=-2e ^{-x}-xe^{-x}+e^{-x}\]
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you use the product rule for the -xe^{-x}
also: \[(e^{u})'=u'\times e^{u}\]
@lego_less check your answer.. it is wrong..
No ur answer is right.
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