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OpenStudy (anonymous):
How many grams of Na2CO3 are present in 19.8 mL of a 32.0% Na2CO3 solution. The density of the solution is 1.15 g/mL.
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OpenStudy (anonymous):
32.0% of Na2CO3 solution means 32grams of Na2CO3 in 100mL of the solvent.. but given only 19.8mL.. so, we have to find out grams of Na2CO3 present in 19.8mL of 32%.. thus, for 100mL ----> 32g then for 19.8mL ---> ?g.. 32 x 19.8/100 = 6.336g.. thus, 6.336g of Na2CO3 is present in 32% of the 19.8mL....
OpenStudy (anonymous):
thank you so much
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