Question

If tan x° =3/y and cos x° =y/z ,what is the value of sin x°?

sin x° = 3/z

sin x° = 3y

sin x° = z/3

sin x° = 3z

Answer 1

Use one of the better-known trigonometric identities:
\[\Large \tan x = \frac{\sin x}{\cos x}\]
Plug in, and you should be able to solve for sin x

Answer 2

but it doesn't give me sin

Answer 3

Okay, you could multiply cos x to both sides of the equation, and it'll give you sin.

Answer 4

but those are letters. idk how

Answer 5

Think of it this way.... say we want c, but we're given
\[\Large a = \frac c b\]
Then we could simply multiply b to both sides
\[\Large a \times b = \frac c b \times b\]
b cancels out on the right side:
\[\Large a\times b = \frac c {\cancel b}\times \cancel b\]
Leaving you with c (all alone)
\[\Large a\times b = c\]

Same concept applies here.

Answer 6

ok

Answer 7

sorry. i'm still confused

Answer 8

All right, in the end, \[\Large \sin(x) = \cos(x)\tan(x)\]