Question

What is the distance between points (9, 4) and (–3, 4) on a coordinate plane?

Answer 1

Distance Formula : \[\sqrt{(x^2-x^1)(y^2-y^2)}\]

Answer 2

lol failed.

Answer 3

i messed up hold on

Answer 4

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 9}}\quad ,&{\color{blue}{ 4}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ 4}})
\end{array}\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)

Answer 5

\[\sqrt{(x^2-x^1)^2(y^2-y^1)^2}\]

Answer 6

there you go.

Answer 7

14?

Answer 8

I don't think so.

Answer 9

-3-9 = 12, square 12 and it gives you 144

Answer 10

4-4= 0, square 0 and it will give you 0

Answer 11

144+0= 144

Answer 12

Now find the square root of 144

Answer 13

12