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integral of sqrt(1+cos2x)dx
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\[\int\limits \sqrt{\left( 1+\cos 2x \right)}dx=\int\limits \sqrt{2\cos ^2x}~dx=\sqrt{2}\int\limits \cos x~dx+c\] =?
@surjithayer where did the one go then when you substituted the 2cos^2x in for cos2x?
It's an identity, @professional_loser_ ^_^ \[\Large 1 = \cos^2(x) + \sin^2(x)\]\[\Large \cos(2x) = \cos^2(x) - \sin^2(x)\] And just add up these two equations :D
thank you! I completely blanked on that identity, lol. @terenzreignz
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