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Question

austinl · Answer

Do you know the definition of domain and range Alley?

tester97 · Answer

no -_- my teacher doesnt TEACH

austinl · Answer

Domain is the $x$ values that the function is allowed to take on.
Range is the $y$ values that the function is allowed to take on.

tester97 · Answer

hmmm i see

tester97 · Answer

so now what do i do?

austinl · Answer

What values of x and y do these functions cover?

austinl · Answer

Oh, and you need to graph it :P

Do you know how to graph these functions?

tester97 · Answer

no :( i asked my teacher but she said figure it out :|

austinl · Answer

Basic form of a circle is this:

$\Large{(x-h)^2+(y-k)^2=r^2}$

$\large{\text{Center}=(h,k)}$

$\large{\text{Radius}=r}$

Soooo,  with this nifty little formula, do you have any thoughts?

tester97 · Answer

how do i find the h?

tester97 · Answer

and the k

austinl · Answer

Well, is there anything after the x or the y in your equation?

tester97 · Answer

what do you mean?

austinl · Answer

$\Large{(x-\color{red}{h})^2+(y-\color{blue}{k})^2=r^2}$

Do you see these values in your initial equation?

$\large{4x^2+4y^2=64}$

tester97 · Answer

64 is after the x and the y

tester97 · Answer

is that what you are looking for?

austinl · Answer

No... 

$\large{4(x-\color{red}{0})^2+4(y-\color{blue}{0})^2=64}$

tester97 · Answer

gahhhhhh where does the 0 come from?

austinl · Answer

$\large{(x-0)^2=~?}$

tester97 · Answer

austin im sorry but im going thru a blonde moment and i dont understand anything right now :(

austinl · Answer

FOIL that out, what do you get? :)

tester97 · Answer

wait i recant that hold on

austinl · Answer

$\large{(x-0)^2=~(x-0)(x-0)=~?}$

tester97 · Answer

just 0 right?

austinl · Answer

FOIL

$\large{(x-0)(x-0)=x^2-0-0+0=~?}$

tester97 · Answer

$$x^2 $$

austinl · Answer

Correctomundo...
Sooo...

$\large{4(x-0)^2=4x^2}$

Correct?

tester97 · Answer

yes i agree

austinl · Answer

So, this should work for the y correct?

tester97 · Answer

indeed

austinl · Answer

Soooo, we have 

$\large{\large{4(x-\color{red}{0})^2+4(y-\color{blue}{0})^2=64}}$

Which means the center is what?

tester97 · Answer

(0,0)

tester97 · Answer

Just realized this looks like a face (0,0) lmao