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solve the equation by factoring (2p-3)(p-4)=0
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(2p-3)(p-4) is already factored
Now you use the zero product property to go from (2p-3)(p-4) = 0 to 2p-3 = 0 or p-4 = 0
my teacher said it wasn't ?
The goal now is to solve 2p-3 = 0 and p-4 = 0 for p
well (2p-3)(p-4) is factored already
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okay thanks for the help anyways ? how about (k+2)(k-1)=0
same idea, (k+2)(k-1)=0 turns into k+2 = 0 or k-1=0
when you use the zero product property
afterwards you solve k+2 = 0 and k-1=0 for k
yeah when u use the 0 property its always zero right?
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it's the idea that if two things multiply to zero, then one of those things must be zero so in algebraic form, if A*B = 0 then either A = 0 or B = 0
okay I got it now thank you !
you're welcome
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