graph the equation. identify the conic sequence, any lines of symmetry, and the domain and range.
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OpenStudy (anonymous):
\[x^2+y^2=4\]
OpenStudy (anonymous):
help @whpalmer4
OpenStudy (whpalmer4):
that's a conic section, not sequence
OpenStudy (whpalmer4):
do you know the general formula for a circle?
OpenStudy (whpalmer4):
or how to describe the points that make up a circle?
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OpenStudy (anonymous):
um not really and lol my bad
OpenStudy (whpalmer4):
Well, a circle is the set of points that are all the same distance from its center, correct?
OpenStudy (anonymous):
yes
OpenStudy (whpalmer4):
Okay. Glad we agree :-)
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OpenStudy (whpalmer4):
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Pythagorean theorem says that \[x^2+y^2 = r^2\]right?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i think
OpenStudy (whpalmer4):
Okay, so that's where the equation for a circle comes from, assuming the center of the circle is at the origin (0,0). If it isn't, then the form becomes
\[(x-h)^2 +(y-k)^2 = r^2\]where the circle's center is at \((h,k)\). I think you can easily convince yourself that that more general equation simplifies to the one you have when \((h,k)=(0,0)\).