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OpenStudy (anonymous):
If the half-life of a 20.0 g sample is known to be 24 minutes, how long will it take for only 5.0 grams of the sample to remain?
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OpenStudy (anonymous):
5g is 1/4 of 20g, so that's 2 half-lives 2x24 = 48 minutes
OpenStudy (dumbcow):
\[e^{-24k} = \frac{1}{2}\] solve for k 5/20 = 1/4 \[e^{-kt} = \frac{1}{4}\] solve for t
OpenStudy (anonymous):
48
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