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3(the square root of) a minus 5 = 13. The teacher said the correct answer was a = 36. I've done similar problems before but I can't figure out how to get a = 36... I did the normal steps, square both sides, etc. Can anyone help me?
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\[3\sqrt{a}-5\]
\[\sqrt[3]{x-5}=13\] or \[3\sqrt{x-5}=13\]
or \[3\sqrt{x}-5=13\]
The second one
3rd example you wrote, second comment
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\[3\sqrt{x}-5=13\] add 5 and get \[3\sqrt{x}=18\] divide by \(3\) to get \[\sqrt{x}=6\]
then square
Thanks so much! I was trying to square first and it was making the problem really complicated.
yeah that will be a pain isolate the radical first if you can
Will do thanks for advice an help!
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