Question

\[\int\limits_{0}^{x} xsin \Pi x\]

Answer 1

there is something wrong here
you cannot have the upper limit of integration by \(x\) and also the integrand by \(x\sin(\pi x)\)

Answer 2

\[\int\limits_{0}^{x} xsin \Pi x\]

Answer 3

but the second fundamental theorem of calculus applies

Answer 4

\[\int_0^xx\sin(\pi x)dx\] makes no sense

Answer 5

you could have \[\int_0^xt\sin(\pi t)dt\] for example

Answer 6

or \[\int_0^{\pi}x\sin(\pi x)dx\] even

Answer 7

okay maybe that's what the teacher meant

Answer 8

can you post the exact question?

Answer 9

that is it

Answer 10

which one?

Answer 11

\[\int\limits\limits_{0}^{x} xsin \Pi xdx\]