Question

Triangles in a circunference

Answer 1

what about them?

Answer 2

So O is the center, and well...there are two triangles...I need to prove that the area of OPB is the same than OPA

Answer 3

I actually got Aopb=2senangle
Aopa=2sen(pi-angle)

Answer 4

u may use below :-
1) semi circle angle = 90
2) median divides a triangle into exactly two equal halves

Answer 5

isnt the angle 180?

Answer 6

angle apb = 90

Answer 7

so that makes "triangle apb" a right triangle

Answer 8

also, "oa = ob" because they both are radii of same circle

Answer 9

Yep, I got that. So it is a right triangle

Answer 10

that makes the segment "po" a median of "triangle apb"

Answer 11

But I need to do demostrations comparing an equation for the area of each triangle

Answer 12

okay, lets find the area of each triangle

Answer 13

They already told me the angle in O is X...And I know the formula for the triangle is (a)(b)(sen)/2

Answer 14

So I got that area of OPB is (1/2)(4)(sen)=2sen
And area of OPA is (1/2)(4)(sen(pi-angle))

Answer 15

do u mean :-

area of opb = \(\large \frac{1}{2} (4) \sin (x) = 2\sin(x)\)

area of opa = \(\large \frac{1}{2} (4) \sin (\pi - x) = 2\sin(\pi - x)\)

Answer 16

??

Answer 17

that looks good, actually u r done :)

Answer 18

look up ur trig identity sheet !

\(\sin (\pi-x) = \sin (x)\)

Answer 19

:O :O :O :O :O

Answer 20

RIGHT!!!!

Answer 21

Thanks, do you think you can help me a little more with this problem?

Answer 22

sure :)

Answer 23

Well...not I get this drawing