Question

1)find the partial derivatives

Answer 1

\[z=x^3+2^y+x^y \] the answer is\[2^yln(2)+x^yln(x)\] how do they get the answer please show your work

Answer 2

its zy

Answer 3

\(z=x^3+2^y+x^y\implies \frac{dz}{dy}=\frac{d(x^3)}{dy}+\frac{d(2^y)}{dy}+\frac{d(x^y)}{dy}\).
the derivative of a^y is ln(a)*y, so
\(\frac{dz}{dy}=0+\ln(2)*2^y+\ln(x)x^y\)

Answer 4

we treat x as a constant.

Answer 5

that should say
the derivative of a^y is ln(a)*a^y

Answer 6

can you please show it step by step

Answer 7

\[d/dy(x^3+2^y+x^y) \]
\[d/dy(x^y)+d/dy(2^y)\]
\[\ln(2)*2^y+\ln(x)*x^y\]
\[2^yln(2)+x^yln(x)\] heres the steps hope it helps=]

Answer 8

thanks

Answer 9

lol how is that any different?

Answer 10

i need the steps for my homework