Question

help!!

Answer 1

@SpooksDF

Answer 2

@whpalmer4

Answer 3

eeeeeeeee! what a problem!

Answer 4

If we look at just the first term in the product:

\[\huge \sqrt[{\ln 4}]{4}\]

By the rules of fractional exponents and radicals, we can rewrite that as \[\huge 4^{\frac{1}{\ln 4}}\]

But what does it mean?

If we take the logarithm base \(b\) of a number \(x\), we get a number \(a\) such that
\[b^a = x\]

That implies that \[\ln 4 =n\]where\[e^n = 4\]