HELP~ SYSTEM OF EQUATIONS Q?
Ralph wants to find the solution to a system of equations using y = x - 2 and y = x2 + 6x - 38. Joey says that Ralph can solve x2 + 5x - 36 = 0 to find the x coordinates of the solutions to his system. Explain and demonstrate why Joey is correct
Oh equality... It has so many strange... qualities LOL
Okay... more to the point, suppose we have a = b and m = n follow?
lol..yeah I'm following. :)
Well then, it shouldn't matter to the first equation if we subtract m from both sides, right? a - m = b - m
You mean to set the y='s to equal each other?
You could do that too ^_^
So then you'll get...? What equation?
y = x - 2 = x^2 + 6x - 38 ?
Okay, and do away with the y in the very left sideand stick to \[\large x-2 = x^2 + 6x - 38\] Now, subtract x-2 from both sides.
Ok, I don't know how to put x -2 into the right side. But the left then is 0
-(x - 2)
Or do it one at a time-- subtract x and then subtract -2 (means add 2)
oh, ok.. X + 6 - 38 ? I'm not sure how to add 2 to the x.
You can only add or subtract similar terms.
Sorry I'm not good at these.:( So x + 12 - 76 ?
You can only add or subtract terms IF they have the EXACT same set of variables attached to them.
Actually, where did 12 and 76 come from?
Well, I first had x + 6 - 38, so I multiplied the 6 and -38 by 2. ?
You did NOT have x + 6 - 38 You had \[\Large x^{\color{red}2}+ 6\color{red}x - 38\]
Yes, and then I subtracted x like you said. Do I just add 2?
You subtract x, and then you get...?
You can only subtract x from 6x.
Oh, 5x, right?
yup. now add the 2 to the -38 Be careful with signs now.
cool, so x^2 + 5x - 36?
yes.. equals zero on the other side. And that's it.
Oh, lol I just realized that equals the third equation! Thanks so much, I get it now:)
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