A cab charges $1.50 for the first mile and $0.50 for each additional mile. Write and solve an inequality to determine how many miles Sharon can travel if she has $25 to spend. $0.50 + $1.50x ≤ $25; x ≤ 16 miles $0.50 + $1.50x ≥ $25; x ≥ 16 miles $1.50 + $0.50x ≤ $25; x ≤ 47 miles $1.50 + $0.50x ≥ $25; x ≥ 47miles Ive narrowed it down to C & D. I get confused on the symbol part?
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First, write a linear expression for the cost of the cab ride. This cost has a fixed component ($25) and a variable component ($0.50 per additional mile) times the number of additional miles). C(x) = ?
1.50 is the fee, which will be your y-intercept, it's what you start with.
$1.50 + $0.50x
0.50 will become 0.50x, where x = additional miles. And 0.50 is your slope.
Yes, that's it Emswizzy.
And it also says how far she can travel with $25. So ≤ 25
Nice work. Thanks for pointing out my mistake (y-intercept $25). Can you put this together? Note: what algebraic expression denotes "additional miles"?
@Emswizzy So what do you think is the answer?
We have: $1.50 + $0.50x and So ≤ 25.
C?
Yes.
!!Thank you so much!!!
No problem :)
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