PLEASE HELP: MEDAL/FAN You need to keep track of your loan four times a month instead of monthly. Solve for the adjusted interest rate. FUNCTION: A (t) = 39,145(1 + (r/12))12t
so... what would I do?
@mathmale @Glizzy_Nedd @undeadknight26 @UnkleRhaukus @mathhelpnow
SO.... What I think is that I plug in the time as 1 month? and I change the rate of .03 to .25?
so... i would get A = 39,145(1 + (0.25/12))12 A = 50, 134 Thats what i got.... but i dont think thats right...
is the answer choice
no... sorry
@undeadknight26 can you help?
plug a number in for t.
would it be 1? cuz t stands for time..... and 1 month?
yup...then 2 then 3 etc...
the formula is A(t) = P(1 + r/n)^nt and the problem says solve for r...
Well no idea in that case o.o
hmmm.... O.O idk
is there more info to this problem ?
Vehicle: Chevy Volt Price: $39,145
The rest of the info is up above
A(t) = P(1 + r/n)^nt P is principle r is rate t is time n is number of times compounded
and it will take 45 months for it to be compounded completely...
i think that's about it....
does this help?
is the rate given 3%?
.03/12=.0025
The question is still unclear. It appears they want to change the compounding to 4 times a month (which is 48 times per year) and then find the new rate? we can change to compounding 48 times per month, by replace 12 with 48 but to solve for the rate, we need more info
that was the original rate..... but i thought you have to find the rate in this problem.... I got this: A (t) = 39,145(1 + r )^(12(-45.5)) --- 12 and solve for r?
yes, if you post it.
I can attach my problem...
Im stuck on problem 3...
to solve for the new r, you need to fill in A(t) on the left side (10,000 ?) because you are compounding 4 times per month, change the 12 to 4*12=48 the exponent was in months. You should change that to weeks (4 wks to a month) so the exponent is -45.5*4
ok
so -182
let me check
if the amount is compounded monthly,you can check the amount more than once but rate will remain same.
you mean A (t) = 39,145(1 + (r /48))^-182 if you compound 4 times per month (= 48 times per year)
oh....
k so im confused on how to solve
The parts 2 and 3 of this question make no sense to me. But if we do what they ask, you get -45.5 months for the answer to part 2. To do part 3, we need to fill in all the variables (except r), and then solve for r
To begin, if you compound 48 times per year, you change your formula to A (t) = 39,145(1 + (r/48))^48t where t is the time in years
Because the question is so goofy, all we can do is take a guess as to what they want. One guess is to solve \[ 10000 = 39145\left(1 + \frac{r}{48}\right)^{48\cdot \frac{-45.5}{12}}\\ 10000 = 39145\left(1 + \frac{r}{48}\right)^{-182} \]
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