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Chemistry 8 Online
OpenStudy (anonymous):

Consider the chemical equilibrium of the following reaction CH3COOH mc015-1.jpg CH3COO– (aq) + H+(aq) What will happen to the chemical equilibrium of the solution if CH3COONa is added? The equilibrium will shifts to the right. The equilibrium will shifts to the left. The equilibrium will be unaffected. The equilibrium will be lost.

OpenStudy (anonymous):

what is mc015-1.jpg

OpenStudy (anonymous):

Oh sorry, it's a little arrow thingy like this <->

OpenStudy (anonymous):

whats the state of CH3COOH?

OpenStudy (anonymous):

I'm not sure, the question doesn't say anything about it

OpenStudy (anonymous):

Do you think you could help me with this one? Consider the chemical equation in equilibrium. 2H2(g) + O2(g) <-> 2H2O(g) What will happen if the pressure of the system is increased? A)The reaction will not change. B)The reverse reaction will be favored. C)The reaction will stop completely. D)The forward reaction will be favored.

OpenStudy (anonymous):

how many moles do you have on the left and right respectively?

OpenStudy (anonymous):

3 on the left and 2 on the right?

OpenStudy (anonymous):

nice! so do you think the reaction will change with pressure given?

OpenStudy (anonymous):

I'm honestly not sure. But I would probably have to guess not

OpenStudy (anonymous):

ok, imagine you have a fish in a plastic bag (like this http://1.bp.blogspot.com/_YsCAFRCuPy4/TO640EnI_LI/AAAAAAAAEgc/oNNTCy6O8xU/s400/1190245184HU567X.jpg) when you squeeze an end of the plastic bag, the fish will "swim"/ being forced to swim to another end

OpenStudy (anonymous):

Okay so the pressure will change, but how do I know which reaction is favored? Like forward or reverse reaction?

OpenStudy (anonymous):

great! now the only question remains is why its shift to left(reverse)/ right(forward) so actually theres a principle that can help you understand the whole thing- Le Chatelier Principle, have you heard of it?

OpenStudy (anonymous):

Yep! Still a little unclear about it though

OpenStudy (anonymous):

its still nice that you've heard of it! its as simple as that -increasing pressure/decreasing volume (basically the same thing) would make equilibrium shift to the fewer moles

OpenStudy (anonymous):

Okay, so the equilibrium would shift towards the right side?

OpenStudy (anonymous):

Le Chatelier's priciples states that a disturbance to a equilibrium system will result in a shift in equilibrium to reduce the change. So what that means for your first question is the addition of CH3COO- Na+ will result in a shift left. "you are adding products so it sifts away from what you added"

OpenStudy (anonymous):

And yes it will shift to the right side!

OpenStudy (anonymous):

for the 2nd question i mean

OpenStudy (anonymous):

That would be correct! You have 3 moles of the left and 2 on the right so an increase in pressure will result in a shift to the side with 2 moles (to the right)

OpenStudy (anonymous):

Okay! Thanks so much you guys!

OpenStudy (anonymous):

no problem, anytime ;)

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