Question

need help .! 8e^(3x)+4=15 use natural logarithms to solve the equation..... il give medal for answer

Answer 1

\[\begin{align*}
8e^{3x}+4&=15\\
8e^{3x}&=11\\
e^{3x}&=\frac{11}{8}\\
\ln\left(e^{3x}\right)&=\ln\frac{11}{8}\\
3x\ln e&=\ln\frac{11}{8}\\
3x&=\ln\frac{11}{8}\\
x&=\frac{1}{3}\ln\frac{11}{8}
\end{align*}\]

Answer 2

which would be -1.124 correct?

Answer 3

No you should have a positive answer.

Answer 4

0.106?

Answer 5

Yes

Answer 6

thank you.!

Answer 7

You're welcome!