Curvature
When. To use |T'(t)|/|r'(t)| and this |r'(t)| x r''(t)|/|r'(t)|^3
@Loser66
Both are the formulas of the curvature but got confused when to implement them
Not sure what you mean :)
For instance find the curvature r(t) = <t,t^2,t^3> at the point (1,1,1)
I got the answer
But why can't we use the 1eqyation
r'(t) = <1,2t, 3t^2> r"(t) =<0,2,6t> cross them to get <6t^2,-6t,2>
My prof said that sometime this way is more convenient: K(x) = \(\dfrac{|f"(x)|}{(1+(f'(x))^2)^3/2}\)
if we are given y = f(x) directly, not a parametric equation
We flexibly use one of them. No need to worry. Like derivative, we can find by limit but why , right? when using theorem is much more convenient
but my question is in paramtric form
u said to use \[|r'(t)| X |r''(t)|/|r'(t)|^3\]
because it is convenient?
yes.
you see, just derivatives
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