Question

calc 2

Answer 1

The x and y are equal in the first quadrant.
Do you remember what angle gives us the same x and y?

Answer 2

if it's too difficult for you to conceptualize, you can instead be more technical and use the identities and stuff.

\[\Large\bf\sf \arctan\left(\frac{y}{x}\right)\quad=\quad \theta\]Plugging in our point,\[\Large\bf\sf \arctan\left(\frac{7}{7}\right)\quad=\quad \theta\]
\[\Large\bf\sf \tan \theta=1\qquad\qquad \implies\qquad\qquad \theta=?\]

Answer 3

0?

Answer 4

No at an angle of 0 degrees, x=1, y=0.
They are not equal to one another there.

Answer 5

sin theta? I'm not sure really

Answer 6

Just look at the picture...
What angle does that `kind of` look like...

Answer 7

90 degrees would be this angle