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Mathematics 20 Online
OpenStudy (anonymous):

Geomtry help please

OpenStudy (anonymous):

OpenStudy (anonymous):

@DSS

OpenStudy (anonymous):

\[6\sqrt{3}\]

OpenStudy (anonymous):

what about next one?

OpenStudy (anonymous):

2nd answer

OpenStudy (anonymous):

34

OpenStudy (anonymous):

and \[17\sqrt{3}\]

OpenStudy (anonymous):

@DSS

OpenStudy (anonymous):

OpenStudy (anonymous):

64+36 = 100 c = 10

OpenStudy (anonymous):

so answer for 1 is C?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[25^{2}-24^{2}=49\] \[\sqrt{49}=7\]

OpenStudy (anonymous):

OpenStudy (anonymous):

You're using the Pythagorean Theorem \[a^2+b^2 = c^2\]

OpenStudy (anonymous):

\[8^2+7^2 = c^2\]

OpenStudy (anonymous):

whts 3 & 4 answes?

OpenStudy (anonymous):

64 + 49 = c^2 113 = c^2 10.6 = c

OpenStudy (anonymous):

Third answer

OpenStudy (anonymous):

question 3 is C?

OpenStudy (anonymous):

\[18^{2}-11^{2^{}}\]=203 answer is \[\sqrt{203}\]

OpenStudy (anonymous):

What would 3 be??? @DSS

OpenStudy (anonymous):

C

OpenStudy (anonymous):

@DSS

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