Question

Find the slope of R= -1+sin theta at the points theta= 0 and theta= pie

Answer 1

yes, polar

Answer 2

oops\[\frac{dy}{dx}=\frac{r'\sin(\theta)+r\cos(\theta)}{r'\cos(\theta)-r\sin(\theta)}\]

Answer 3

in your case \(r=-1+\sin(\theta)\) and \(r'=\cos(\theta)\)

Answer 4

i got the derivative part, it is just the limits are confusing me, what am i suppose to do with me?

Answer 5

Plug them in.

Answer 6

Those are not limits; they are distinct points.

Answer 7

what @primeralph said, evaluate
unless you get \(\frac{0}{0}\)

Answer 8

oh, so plug both of them into the tangent equation and get two separate tangents??

Answer 9

Yes.

Answer 10

Tangents are at points; integrals are over bounds (limits).

Answer 11

thanks!!

Answer 12

Well, you're easy to teach. You seem smart already, so keep it up.