Josh starts his sled at the top of a 3.2m -high hill that has a constant slope of 25 ∘ . After reaching the bottom, he slides across a horizontal patch of snow. The hill is frictionless, but the coefficient of kinetic friction between his sled and the snow is 0.08. How far from the base of the hill does he end up?

Question

abb0t · Answer

Note that: K.E$_{f}$ = P.E $_i$

nottim · Answer

including frictional force?

abb0t · Answer

the Kinetic Energy of final = mgh
which is m(9.81)(3.2)

nottim · Answer

We aren't at energy in my course yet.

nottim · Answer

This course, even though I have learned, but forgotten about it.

abb0t · Answer

31.36 m/Jule
by Work Energy theorem, 
work done by friction = $\Delta$KE
force done by friction
$\sf \mu$ks = 31.36
solve for $s$

nottim · Answer

where did you get 31.36?

abb0t · Answer

9.81(3.2)

nottim · Answer

mew k is oone variablE?

anonymous · Answer

This is like a two stage problem.. 
first you need to evaluate what is the velocity he gains at the base of the hill.. did u do that?