How do you balance Cu3(PO4)2 + AgNO3 =
first, determine what the products of the reaction will be
so in this case, most likely you will have a double replacement where the Cu cation switches anions with the Ag cation. Determine each ion's charges
silver is +1, NO3 is -1, PO4 is always a -3, and Cu must be +2 because it takes 3 Cu ions and 2 PO4 ions to make the entire molecule neutral. (2*-3+3*2=-6+6=0
then, rearrange the molecules, replacing the Cu3(PO4)2 anion with the AgNO3 anion. this produces Cu(NO3)2 and Ag3PO4
from there, list out your molecules in the equation and change coefficients until there are equal numbers of the same atom on either side of the equation.
adjust until you end with matching numbers of atoms/ions
looks like this: Cu3(PO4)2+AGNO3 ==> Cu(NO3)2+Ag3PO4 Reactants Products Cu-3 Cu-1 PO4-2 PO4-1 Ag-1 Ag-3 NO3-1 NO3-1
I still do not get it, you have on one side 3 Cu and on the other side only 1 Cu, I thought you have to balance it so the one side has the same number as the other ???
2Cu3(PO4)2 + 6AgNO3 = 2Ag3(PO4) + 6CuNO3
did u get now @kajal
no because you have on one side 2X(PO4)2 =4, and on the other side only 2(PO4) ,
2Cu3(PO4)2 + 6AgNO3 = 6CuNO3+2Ag3(PO4)2 maybe???
Cu3(PO4)2 + 3 AgNO3 = 3 CuNO3 + Ag3(PO4)2 or this?
ur right lol :(
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