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In polynomial vector space, is P (ax) = a P(x)? Please help
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@Loser66, it's been a while since I've had linear algebra, but any element in this vector space would have the form \(a_0+a_1x+a2x^2+\cdots+a_nx^n\), correct?
yes, I think so.
I think it is not equal Let P(x) = x^2 +3 P(2x) = (2x)^2 +3 \(\neq\)2P(x) = 2x^2 +6 am I right?
Yeah, that's what I was thinking.
It would only work for \(n<2\).
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but the problem ask me: Prove that it is a linear transformation: V is P; if x is a polynomial, then (Ax)(t) = x(t+1)-x(t) Does it imply that A is a linear transformation?
which is A(aX(t) = aA(X)(t) = aAX(t)
Hmm, I'm not so familiar with any of this notation... Sorry.
It's ok, I am confused everything, hehehe...
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