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OpenStudy (anonymous):
Find the volume of 0.100M hydrochloric acid necessary to react completely with 1.51g Al(OH)3.
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OpenStudy (gebooors):
Calculate first molar mass M and amount of substance n of Al(OH)3. Then you see you need 3 moles HCl for one mole Al(OH)3. Then n = concentration * volume, n = cV. You get volume in litres.
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