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OpenStudy (anonymous):
Calculate the total number of ions present in 60.0g of SrCl2. Enter the answer in scientific notation. My step: (60.0 g SrCl2) x (1 mol SrCl2/150.53g)=3.784 x10^-1 mol SrCl2 3(3.784x10^-1) x (6.02x10^23) = 6.83x10^23 Is it correct?
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OpenStudy (anonymous):
YES!!! :)
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