5/7x+2/7y=1
6x+y=11
place your answer in the form of (x,y)

Question

5/7x+2/7y=1
6x+y=11
place your answer in the form of (x,y)

mathmale · Answer

5/7x+2/7y=1$$5/7x+2/7y=1$$
really should be written as$$\frac{ 5 }{ 7 }x+\frac{ 2 }{ 7 }y=1$$ for greater clarity.
It'd be much easier if we were to eliminate fractions in this equation.  The LCD of this equation is 7.

So , please multiply each term by 7 to eliminate fractions.

anonymous · Answer

ok

mathmale · Answer

Candy, "OK" is not a proper or helpful response here.  I'm asking you to do something; if you can, please do it.  Multiply each term by 7 and write out the result$$7(\frac{ 5 }{ 7 }x+\frac{ 2 }{ 7 }y=1)$$

anonymous · Answer

please help

mathmale · Answer

I don't understand your situation at all, really.  Why is it (apparently) so hard for you to multiply (5/7) by 7?

anonymous · Answer

yes it is

mathmale · Answer

Please re-read my question.  You didn't answer my question.

anonymous · Answer

i'm blind

mathmale · Answer

You can see well enough to respond quickly to whatever I type.  If you are willing and able to hold up your end of a conversation meant to help you solve a problem, fine, let's do that.  I need your involvement.  "OK" simply doesn't cut it as an answer.  
Please go back and multiply that equation by 7 as I asked you to do earlier.

mathmale · Answer

Multiply each term within parentheses by 7:$$7(\frac{ 5 }{ 7 }x+\frac{ 2 }{ 7 }y=1)$$

Result:  5x + 2y = 7
Your other equation is 
             6x+y=11

This system of linear equations is slightly easier to solve because the fractions are gone.

What must you do next to find a solution?