Question

I've tried doing this but I don't get it!

Simplify.

(–8x) ÷ (–2)

A.
2x

B.
16x

C.
4x

D.

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Answer 1

\[\large \frac{-8x}{-2}\]

Well you know that a negative divided by a negative is positive...so

\[\large \frac{8x}{2}\]

Now note...

\[\large \frac{8x}{2} = \frac{8}{2} \times x = 4x\]

I hope that makes sense?

Answer 2

Sorta makes sense, thank you :)

Answer 3

When you get down to

\[\large \frac{8x}{2}\] all you really do is divide the numbers like normal...but remember at the end...you need to carry along the 'x'...

so 8/2 is the 4 ...but we still have the 'x' ...so 4 times x = 4x