Question

Find the average value of the function h(y) = 8e^(4y) on the interval [-1, 2].

Answer 1

\[\frac{1}{2-(-1)} \int_{-1}^{2} 8e^{4y} \, dy\]

Answer 2

\[\int_{-1}^2 8e^{4y} \, dy = \left[2e^{4y} \right]_{-1}^2\]

Answer 3

2(e8 - e-4) then?

Answer 4

then divided by three

Answer 5

Yeah.

Answer 6

thank you!