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If n > 1 and y = log n x, find dy/dx.
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Did you mean \(y=\log(nx)\)?
If so, recall that the derivative of \(\ln(x)\) is \(\frac{1}{x}\) and use the chain rule.
(Assuming you're using \(\log\) to mean the natural logarithm, not base 10.)
ah, n is actually the base! \[\log_{n}x\]
Oh, then the rule to use is \(\log_a(b)^{\prime} = \frac{1}{x\ln(a)}\).
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I started with a b and ended with an x there, sorry.
So in your case you would get \[\frac{1}{x\ln(n)}\]
okay, i understand now! thank you. the n instead of a constant confused me.
You can treat any variables besides the one you're taking a derivative with respect to as constants.
(As long as they aren't functions of your variable, \(y(x)\) obviously isn't a constant.)
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