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the correct ratio of moles of NAHCO2 used to moles of CO2 produced in the reaction of NaHCO3(s) + HC2H3O2(aq) = H2O + CO2(g) + NaC2H3O2(aq) is 1 to 1. when you use 2.80 g of NaHCO3 and determine that 2.83 g of carbon dioxide are produced, compare the moles of the NaHCO3 and CO2, and explain how the ratio is 1 to 1.
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