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Mathematics 9 Online
OpenStudy (anonymous):

Can someone tell me what I did wrong? Please In the diagram BE and AD pass through the center of circle 0 and the area sector AOC is 47.45 square units. What is the area of sector BOC? Use the value pi=3.14 and round your answer to two decimal places. I had done it this way but was wrong. HELP PLEASE!!!! 40/360*3.14(0.8)^2 0.2233 22.33

OpenStudy (anonymous):

OpenStudy (anonymous):

@eliassaab HELP PLEASE I'm doing something wrong

OpenStudy (phi):

It looks like you found the area of sector AOB

OpenStudy (phi):

although you should use radius= 8 (not 0.8)

OpenStudy (anonymous):

I would still get the wrong answer is my formula wrong???

OpenStudy (phi):

the next step is to notice that the areas of sector AOB + sector BOC together add up to the area of sector AOC they tell you the area of AOC= 47.45 using your answer for the area of AOB= 22.33 we can say area BOC + 22.33= 47.45

OpenStudy (phi):

you correctly found the area of sector AOB but I would write it as 40/360*3.14* 8^2 = 22.33

OpenStudy (anonymous):

then I would get 25.12 is there an easier way to do this?

OpenStudy (phi):

There is no easier way. It is a two step process. It is good to go through the thinking, to make sure it makes sense.

OpenStudy (anonymous):

Thank you so I need to remember the two steps here!

OpenStudy (anonymous):

Let x be the angle AOC \[ \frac{1}{360} 3.14 8^2 x=47.45\\ x=85= \text {angle } AOC\\ \text{ angle } BOC= 85- 40=45\\ \text { then the area of BOC is} \\ \frac{1}{360} (3.14) 8^2 (45)=25.12 \]

OpenStudy (anonymous):

40/360*3.14*8^2 =22.33 BOC+22.33=47.45 BOC=25.12

OpenStudy (anonymous):

Thank you @eliassaab

OpenStudy (anonymous):

YW

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