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6. the ratio of the volumes of the two spheres is 27:343 and the sum of their radii is 10. find the radius of the smaller sphere.
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let V1 and V2 be the volumes. Then\[\frac{ V1 }{ V2 }=\frac{ 27 }{ 343 }=\frac{\frac{ 4 }{ 3 } \pi \left( R1 \right)^3 }{ \frac{ 4 }{ 3 }\pi \left( R2 \right)^3 }\] Where R1 and R2 arethe radii of the two spheres. \[\left( \frac{ R1 }{ R2 } \right)^3=\frac{ 27 }{343 }=\left( \frac{ 3 }{ 7 } \right)^3\] \[\frac{ R1 }{R2 }=\frac{ 3 }{7 },R1=\frac{ 3 }{ 7 }R2\] Also R1+R2=10 \[\frac{ 3 }{7 }R2+R2=10,3R2+7R2=10*7,10R2=70,R2=70/10=7\] find R1
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