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Please HELP! Factor this expression completely. x^3 + 1/8
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Use the formula \[ a^3+b^3=(a+b) \left(a^2-a b+b^2\right) \]
a=x b=1/2
Im not sure
Hint: Look up "special products and factoring" in your textbook or online. Note that x^3 - 1/8 can be written as \[x^3+(1/2)^3.\] which has the same form as the (a^3+b^3) mentioned by eliassaab.
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so would it be (x + 1/2) ( x^2- x1/2 + 1/2^2) ??
Yes
\[ \left(x+\frac{1}{2}\right) \left(x^2-\frac{x}{2}+\frac {1}{4}\right) \]
Nice work, Power2Knowledge!!
thanks
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