A 74-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 842 N. What is the acceleration of the elevator?

Question

anonymous · Answer

$$F _{N}=mg+ma _{E}$$
$$F _{N}=m(g+a _{E})$$

anonymous · Answer

That should get you started. =)

anonymous · Answer

@nnn123
if that man stood on a weighing scale (which apparently reads in Newtons in this problem), then it would read 74 X 10 = 740 Newtons.. right? (g = 10m/s^2) 

but can you tell me why would the scale read any different, when the elevator rises ?